## Mass generation: The solution

In my preceding post I have pointed out an interesting mathematicalquestion about the exact solutions of the scalar field theory that I use in this paper

$\Box\phi+\lambda\phi^3=0$

given by

$\phi=\mu\left(\frac{2}{\lambda}\right)^\frac{1}{4}{\rm sn}(p\cdot x,i)$

that holds for

$p^2=\mu^2\sqrt{\frac{\lambda}{2}}.$

If you compute the Hamiltonian the energy does not appear to be finite, differently from what the relation dispersion is saying. This is very similar to what happens to plane waves for the wave equation. The way out is to take a finite volume and normalize properly the plane waves. One does this to get the integral of the Hamiltonian finite and all amounts to a proper normalization. In our case where must this normalization enter? The striking answer is: The coupling. This is an arbitrary parameter of the theory and we can properly rescale it to get the right normalization in the Hamiltonian. The final result is a running coupling exactly in the same way as I and others have obtained for the quantum theory. You can see the coupling entering in the right way both in the solution and in the computation of the Hamiltonian.

If you are curious about these computations you can read the revised version of my paper to appear soon on arxiv.

Marco Frasca (2010). Mass generation and supersymmetry arxiv arXiv: 1007.5275v1

### 2 Responses to Mass generation: The solution

Hi Marco

I do not understand how coupling can be arbitrary parameter. Does that mean it has no influence?

Also, I think that mass is a phenomenological parameter that is simply written as such by definition. Why one should “generate” mass? What if the “generated mass” does not correspond to any experiment?

• mfrasca says: